Problem: The solubility of magnesium phosphate is 3.32 x 10 -4 g/L (MM = 262.9 g/mol) Calculate the Ksp for Mg3(PO4)2 (REMEMBER: g/L)!! a. 6.4x10-42b. 2.11x10-21c. 7.22x10-18d. 9.5x10-26e. 3.5x10-28

FREE Expert Solution

Figure out the Ksp equation of magnesium phosphate(Mg3(PO4)2) and determine the Ksp using the provided concentration of 3.32 x 10 -4 g/L 

For this problem, we need to follow these steps:

Step 1. Convert g/L to M for the provided concentration

Step 2. Setup the Ksp equation then construct an ICE table

Step 3. Calculate Ksp


Step 1. Initially,we are given a concentration in g/L which is needed to converted to M or mol/L. 

Calculating the M of Mg3(PO4)2

[Mg3(PO4)2] = moles Mg3(PO4)21 L[Mg3(PO4)2] = (3.32x10-4 g1 L)(1 mol262.9 g)

[Mg3(PO4)2] = 1.2628x10-6


Step 2. The dissociation of Mg3(PO4)2 in water are as follows:

Mg3(PO4)2(s)  ⇌  3 Mg2+ (aq) + 2 PO43- (aq)


We can construct an ICE table for the dissociation of Mg3(PO4)2. Remember that solids are ignored in the ICE table.

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Problem Details

The solubility of magnesium phosphate is 3.32 x 10 -4 g/L (MM = 262.9 g/mol) Calculate the Ksp for Mg3(PO4)2 (REMEMBER: g/L)!! 

a. 6.4x10-42

b. 2.11x10-21

c. 7.22x10-18

d. 9.5x10-26

e. 3.5x10-28

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