Figure out the Ksp equation of magnesium phosphate(Mg3(PO4)2) and determine the Ksp using the provided concentration of 3.32 x 10 -4 g/L
For this problem, we need to follow these steps:
Step 1. Convert g/L to M for the provided concentration
Step 2. Setup the Ksp equation then construct an ICE table
Step 3. Calculate Ksp
Step 1. Initially,we are given a concentration in g/L which is needed to converted to M or mol/L.
Calculating the M of Mg3(PO4)2
[Mg3(PO4)2] = 1.2628x10-6
Step 2. The dissociation of Mg3(PO4)2 in water are as follows:
Mg3(PO4)2(s) ⇌ 3 Mg2+ (aq) + 2 PO43- (aq)
We can construct an ICE table for the dissociation of Mg3(PO4)2. Remember that solids are ignored in the ICE table.
The solubility of magnesium phosphate is 3.32 x 10 -4 g/L (MM = 262.9 g/mol) Calculate the Ksp for Mg3(PO4)2 (REMEMBER: g/L)!!
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