Problem: Pa-227 undergoes alpha decay. What is the product nucleus? Enter your answer using the same format, i.e, symbol-mass number

We’re being asked to identify the product nucleus when Pa-227 (²²⁷₉₁Pa) undergoes alpha decay.

Recall that in a nuclear reaction, the number of protons and neutrons are affected and the identity of the element changes. For alpha decay, an alpha particle (⁴₂α, atomic mass = 4, atomic number = 2) is formed as a product.