Problem: Given the values of ΔGf° given below in kJ/mol calculate the value of ΔG° in kJ for the reaction,NH3(g) + HBr(g) =&gt; NH4Br(s)ΔGf° (NH3(g)) = -17ΔGf° (HBr(g)) = -52ΔGf° (NH4Br(s)) = -177a. 108 kJb. 212 kJc. -108 kJd. -212 kJe. -246 kJ

FREE Expert Solution

We’re being asked to calculate the value of ΔG° in kJ for the given reaction:

NH3(g) + HBr(g) → NH4Br(s)

We can use the following equation to solve for ΔG˚rxn:

The values for ΔG˚f can be looked up in textbooks or online:

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Problem Details

Given the values of ΔGf° given below in kJ/mol calculate the value of ΔG° in kJ for the reaction,

NH3(g) + HBr(g) => NH4Br(s)

ΔGf° (NH3(g)) = -17

ΔGf° (HBr(g)) = -52

ΔGf° (NH4Br(s)) = -177

a. 108 kJ
b. 212 kJ
c. -108 kJ
d. -212 kJ
e. -246 kJ

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