# Problem: Calculate E°(cell) for the reaction, 2 IO3-(aq) + 10 Fe2+(aq) &lt;=&gt; 10 Fe3+(aq) + I2(aq) given the reduction potentials:Fe3+(aq) + e- ⇌ Fe2+(aq) ,                  E° = 0.77 V2 IO3-(aq) + 10 e- ⇌ I2(aq),                E° = 1.10 Va. 0 Vb. -0.33 Vc. +0.33 Vd. -1.87 Ve. +0.87 V

###### FREE Expert Solution

We’re asked to determine the Ecell  for the half-reactions:

Fe3+(aq) + e<=> Fe2+(aq) ,                  E° = 0.77 V

2 IO3-(aq) + 10 e- <=> I2(aq),                E° = 1.10 V

For this problem, we have to determine the anode and cathode reactions:

Loss of Electron is an Oxidation process undergone by the Reducing Agent (LEORA). In the Anode, Oxidation happens (An Ox)

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###### Problem Details

Calculate E°(cell) for the reaction, 2 IO3-(aq) + 10 Fe2+(aq) <=> 10 Fe3+(aq) + I2(aq) given the reduction potentials:

Fe3+(aq) + e⇌ Fe2+(aq) ,                  E° = 0.77 V

2 IO3-(aq) + 10 e⇌ I2(aq),                E° = 1.10 V

a. 0 V

b. -0.33 V

c. +0.33 V

d. -1.87 V

e. +0.87 V