We’re asked to determine the Ecell for the half-reactions:
Fe3+(aq) + e- <=> Fe2+(aq) , E° = 0.77 V
2 IO3-(aq) + 10 e- <=> I2(aq), E° = 1.10 V
For this problem, we have to determine the anode and cathode reactions:
Loss of Electron is an Oxidation process undergone by the Reducing Agent (LEORA). In the Anode, Oxidation happens (An Ox)
Calculate E°(cell) for the reaction, 2 IO3-(aq) + 10 Fe2+(aq) <=> 10 Fe3+(aq) + I2(aq) given the reduction potentials:
Fe3+(aq) + e- ⇌ Fe2+(aq) , E° = 0.77 V
2 IO3-(aq) + 10 e- ⇌ I2(aq), E° = 1.10 V
a. 0 V
b. -0.33 V
c. +0.33 V
d. -1.87 V
e. +0.87 V
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What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Cell Potential concept. If you need more Cell Potential practice, you can also practice Cell Potential practice problems.
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Our tutors rated the difficulty ofCalculate E°(cell) for the reaction, 2 IO3-(aq) + 10 Fe2+(aq...as medium difficulty.
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Based on our data, we think this problem is relevant for Professor Fakhreddine's class at TEXAS.