# Problem: The standard free energy for a reaction is ΔG° = – 33.0 kJ. At 25°C the equilibrium constant for this reaction , Kp = ________. Enter your answer in exponential format (sample 1.23E-4) with two decimal places and no units.

###### FREE Expert Solution

We’re being asked to determine the equilibrium constant for this reaction , Kp  at 25 ˚C

Recall that ΔG and Kp are related to each other:

$\overline{){\mathbf{\Delta G}}{{\mathbf{°}}}_{{\mathbf{rxn}}}{\mathbf{=}}{\mathbf{-}}{{\mathbf{RTlnK}}}_{{\mathbf{p}}}}$

We’re given:

R = 8.314 J/mol • K

ΔG° = – 33.0 kJ

T = 25 ˚C + 273 = 298 K

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###### Problem Details

The standard free energy for a reaction is ΔG° = – 33.0 kJ. At 25°C the equilibrium constant for this reaction , Kp = ________. Enter your answer in exponential format (sample 1.23E-4) with two decimal places and no units.

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