Problem: If a log contains 60.0% of the 14C present in a living tree, how long (yr) has the log been dead? The half-life of 14C is 5715 years. Enter your answer as a whole number with no units.

FREE Expert Solution

We’re being asked to determine how long the age has been dead. 


Recall that half-life is the time needed for the amount of a reactant to decrease by 50% or one-half


The half-life of a first-order reaction is given by:


t1/2 = ln 2k


where:

t1/2 = half-life

k = decay constant


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Problem Details

If a log contains 60.0% of the 14C present in a living tree, how long (yr) has the log been dead? The half-life of 14C is 5715 years. Enter your answer as a whole number with no units.

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the First Order Half Life concept. You can view video lessons to learn First Order Half Life. Or if you need more First Order Half Life practice, you can also practice First Order Half Life practice problems.