Problem: At 298 K, ΔG°f is -620 kJ/mol for SiCl4(g) and -592 kJ/mol for MgCl2(s). Calculate ΔG° (kJ) for the reaction below at 298 K if the pressure of SiCl4(g) is 1 atm. Enter your answer as the nearest whole number with no units. SiCl4(g) + 2Mg(s) --> Si(s) + 2 MgCl2(s)

FREE Expert Solution

We’re being asked to determine the ΔG° (kJ) for the reaction below at 298 K:


SiCl4(g) + 2 Mg(s) → Si(s) + 2 MgCl2(s)



We can use the following equation to solve for ΔG˚rxn:


ΔG°rxn=ΔG°f, prod-ΔG°f, react


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Problem Details

At 298 K, ΔG°f is -620 kJ/mol for SiCl4(g) and -592 kJ/mol for MgCl2(s). Calculate ΔG° (kJ) for the reaction below at 298 K if the pressure of SiCl4(g) is 1 atm. Enter your answer as the nearest whole number with no units. 

SiCl4(g) + 2Mg(s) --> Si(s) + 2 MgCl2(s)

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