Balancing Redox Reaction Video Lessons

Concept

# Problem: Balance the following equation in basic solution using the lowest possible integers and give the coefficient of water.MnO4-(aq) + SO32-(aq) → MnO2(s) + SO42-(aq)a. 3b. 2c. 0d. 1e. 4

###### FREE Expert Solution

We are being asked to balance the given redox reaction occurring in a basic solution and give the coefficient of water

When balancing redox reactions under basic conditions, we will follow the following steps.

Step 1. Separate the whole reaction into half-reactions
Step 2. Balance the non-hydrogen and non-oxygen elements first
Step 3. Balance oxygen by adding H2O to the side that needs oxygen (1 O: 1 H2O)
Step 4. Balance hydrogen by adding H+ to the side that needs hydrogen (1 H: 1 H+)
Step 5. Balance the charges: add electrons to the more positive side (or less negative side)
Step 6. Balance electrons on the two half-reactions
Step 7. Get the overall reaction by adding the two reaction
Step 8. Balance remaining H+ by adding an equal amount of OH- ions to both sides
Step 9. H+(aq) will combine with OH-(aq) to form H2O(l)­
Step 10. Cancel out common species.

Balance the redox reaction under basic condition:

MnO4-(aq) + SO32-(aq) → MnO2(s) + SO42-(aq)

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###### Problem Details

Balance the following equation in basic solution using the lowest possible integers and give the coefficient of water.

MnO4-(aq) + SO32-(aq) → MnO2(s) + SO42-(aq)

a. 3
b. 2
c. 0
d. 1
e. 4