# Problem: Given that the ΔGf° (kJ/mol) at 298 K for difluoroacetylene (C2F2) and hexafluorobenzene (C6F6) are 185.3 and 81.3, respectively, what is K at 298 K for the reaction, C6F6(g) ↔ 3C2F2(g)? a. 1.41 × 1083b. 5.88 × 10-19c. 1.70 × 10-18d. 6.41 × 10-84e. 5.34 × 10-11

###### FREE Expert Solution

We’re being asked to determine the equilibrium constant (K) at 298 K for the given reaction:

C6F6(g)  3C2F2(g)

Recall that ΔG˚rxn and K are related to each other:

$\overline{){\mathbf{\Delta G}}{{\mathbf{°}}}_{{\mathbf{rxn}}}{\mathbf{=}}{\mathbf{-}}{\mathbf{RTlnK}}}$

We can use the following equation to solve for ΔG˚rxn:

###### Problem Details

Given that the ΔGf° (kJ/mol) at 298 K for difluoroacetylene (C2F2) and hexafluorobenzene (C6F6) are 185.3 and 81.3, respectively, what is K at 298 K for the reaction, C6F6(g) $↔$ 3C2F2(g)?

a. 1.41 × 1083
b. 5.88 × 10-19
c. 1.70 × 10-18
d. 6.41 × 10-84
e. 5.34 × 10-11