# Problem: What is the value of Kc for the reaction H2(g) + F2(g) &lt;=&gt; 2HF(g) given that when 0.010 mol H2 and 0.050 mol F2 are added to a 1.00 L container, 0.0125 mol HF is present at equilibrium.a. 3.1x101b. 2.5x102c. 9.5x10-1d. 7.6x101e. 1.1

###### FREE Expert Solution

We are being asked to calculate the equilibrium constant, Kc for the given equilibrium reaction:

H2(g) + F2(g) ⇌ 2 HF(g)

When dealing with equilibrium and Kc:

Kc → equilibrium units are in molarity
Kc is an equilibrium expression:

$\overline{){{\mathbf{K}}}_{{\mathbf{c}}}{\mathbf{=}}\frac{\mathbf{products}}{\mathbf{reactants}}}$

only aqueous and gaseous species are included in the equilibrium expression
▪ the coefficient of each compound in the reaction equation will be the exponent of the concentrations in the equilibrium expression

Recall molarity:

Given:

89% (24 ratings)
###### Problem Details

What is the value of Kc for the reaction H2(g) + F2(g) <=> 2HF(g) given that when 0.010 mol H2 and 0.050 mol F2 are added to a 1.00 L container, 0.0125 mol HF is present at equilibrium.

a. 3.1x101
b. 2.5x102
c. 9.5x10-1
d. 7.6x101
e. 1.1