Chemistry Practice Problems Boiling Point Elevation Practice Problems Solution: Lanthanum(III) chloride dissolves in water accordi...

Solution: Lanthanum(III) chloride dissolves in water according to: LaCl3(s) → La3+(aq) + 3 Cl-(aq). What is the boiling point of the solution when 0.2453 g of LaCl3 (molar mass 245.3 g/mol) is dissolved in 10.0 g of H2O? (Kb of water is 0.512 °C/m.)a. 100.051°Cb. 100.154°Cc. 100.102°Cd. 100.205°Ce. 100.512°C

Problem

Lanthanum(III) chloride dissolves in water according to: LaCl3(s) → La3+(aq) + 3 Cl-(aq). What is the boiling point of the solution when 0.2453 g of LaCl(molar mass 245.3 g/mol) is dissolved in 10.0 g of H2O? (Kb of water is 0.512 °C/m.)

a. 100.051°C
b. 100.154°C
c. 100.102°C
d. 100.205°C
e. 100.512°C

Solution

We’re being asked to determine the boiling point of a solution. The solution is prepared by dissolving 0.2453 g of LaCl3 in 10 g of water


Recall that the boiling point of a solution is higher than that of the pure solvent and the change in boiling point (ΔT­b) is given by:


Tb=Tb, soluon-Tb, pure solvent


The change in boiling point is also related to the molality of the solution:


Tb=iKbm

where: 

i = van’t Hoff factor

m = molality of the solution (in m or mol/kg)

Kb = boiling point elevation constant (in ˚C/m)


Recall that the Molality of a solution is given by:


molality(m)=moles solutekg solvent


Solution BlurView Complete Written Solution