We’re being asked to **determine an expression** that represents **mass percent** of H_{2}SO_{4 }in **2.00 m aqueous** H_{2}SO_{4 }solution.

Recall that ** molality** is the ratio of the moles of solute and the mass of solvent (in kilograms).

In other words:

$\overline{){\mathbf{Molality}}{\mathbf{\left(}}{\mathbf{m}}{\mathbf{\right)}}{\mathbf{=}}\frac{\mathbf{moles}\mathbf{}\mathbf{solute}}{\mathbf{kg}\mathbf{}\mathbf{solvent}}}$

Recall the **mass percent formula** shown below:

$\overline{){\mathbf{mass}}{\mathbf{}}{\mathbf{percent}}{\mathbf{=}}\frac{\mathbf{mass}\mathbf{}\mathbf{component}}{\mathbf{total}\mathbf{}\mathbf{mass}}{\mathbf{\times}}{\mathbf{100}}}$

Since we are dealing with a **solution**, we can rewrite the equation as:

$\overline{){\mathbf{\%}}{\mathbf{}}{\mathbf{mass}}{\mathbf{=}}\frac{\mathbf{mass}\mathbf{}\mathbf{solute}}{\mathbf{mass}\mathbf{}\mathbf{solution}}{\mathbf{\times}}{\mathbf{100}}}$

Which of the following represents the mass percent of H_{2}SO_{4} (MM = 98) in a 2.00 m aqueous H_{2}SO_{4 }solution?

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Molality concept. You can view video lessons to learn Molality. Or if you need more Molality practice, you can also practice Molality practice problems.

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