# Problem: Given that the ∆G°f (kJ/mol) at 298 K for difluoroacetylene (C2F2) and hexafluorobenzene (C6F6)  are 185.3 and 81.3, respectively, what is K at 298 K for the reaction, C6F6(g) ↔ 3C2F2(g)?a. 5.88x10-19b. 8.25x10-1c. 1.56x10-83d. 5.34x10-11e. 6.41x10-84

###### FREE Expert Solution

We’re being asked to determine the equilibrium constant (K) at 298 K for the given reaction:

C6F6(g) ↔ 3C2F2(g)

Recall that ΔG˚rxn and K are related to each other:

$\overline{){\mathbf{\Delta G}}{{\mathbf{°}}}_{{\mathbf{rxn}}}{\mathbf{=}}{\mathbf{-}}{\mathbf{RTlnK}}}$

We can use the following equation to solve for ΔG˚rxn:

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###### Problem Details

Given that the ∆G°f (kJ/mol) at 298 K for difluoroacetylene (C2F2) and hexafluorobenzene (C6F6)  are 185.3 and 81.3, respectively, what is K at 298 K for the reaction, C6F6(g) ↔ 3C2F2(g)?

a. 5.88x10-19
b. 8.25x10-1
c. 1.56x10-83
d. 5.34x10-11
e. 6.41x10-84

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