Problem: Given that the ∆G°f (kJ/mol) at 298 K for difluoroacetylene (C2F2) and hexafluorobenzene (C6F6)  are 185.3 and 81.3, respectively, what is K at 298 K for the reaction, C6F6(g) ↔ 3C2F2(g)?a. 5.88x10-19b. 8.25x10-1c. 1.56x10-83d. 5.34x10-11e. 6.41x10-84

FREE Expert Solution

We’re being asked to determine the equilibrium constant (K) at 298 K for the given reaction:

C6F6(g) ↔ 3C2F2(g)


Recall that ΔG˚rxn and K are related to each other:


ΔG°rxn=-RTlnK


We can use the following equation to solve for ΔG˚rxn:


ΔG°rxn=ΔG°f, prod-ΔG°f, react


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Problem Details

Given that the ∆G°f (kJ/mol) at 298 K for difluoroacetylene (C2F2) and hexafluorobenzene (C6F6)  are 185.3 and 81.3, respectively, what is K at 298 K for the reaction, C6F6(g) ↔ 3C2F2(g)?

a. 5.88x10-19
b. 8.25x10-1
c. 1.56x10-83
d. 5.34x10-11
e. 6.41x10-84