We’re being asked to calculate for the molality of a solution prepared by dissolving 10.66 g of potassium chlorate in 74.9 g of water.
When calculating for molality, we use the following equation:
solution → water is the solvent (H2O)
solute → potassium chlorate
Potassium → Group 1A → +1 charge → K+
Chlorate → polyatomic ion → ClO3-
We will calculate the molality of the solution using the following steps:
Determine the molality of a solution prepared by dissolving 10.66 g of potassium chlorate in 74.9 g of water. Give your answer to 2 decimal places.
a. 0.14 m
b .1.16 m
c. 0.96 m
d .1.16x10-3 m
e. 1.40x103 m
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