# Problem: Determine the volume in mL of 0.3 M HI(aq) needed to reach the half-equivalence (stoichiometric) point in the titration of 41 mL of 0.47 M (CH3)2NH(aq)(aq).  The Kb of dimethylamine is 5.4 x 10-4.

###### FREE Expert Solution

We are asked to determine the volume in mL of 0.3 M HI(aq) needed to reach the half-equivalence (stoichiometric) point in the titration of 41 mL of 0.47 M (CH3)2NH(aq).

At the half-equivalence point, half of the moles of (CH3)2NH(aq) will be consumed.

We'll go through the following steps to solve the problem

Step 1. Calculate the moles of  (CH3)2NH(aq)

Step 2. Calculate half of the moles of (CH3)2NH(aq)

Step 3. Calculate the volume of 0.3 M needed for half of the moles of (CH3)2NH(aq)

Step 1. Calculate the moles of  (CH3)2NH(aq)

recall: ###### Problem Details

Determine the volume in mL of 0.3 M HI(aq) needed to reach the half-equivalence (stoichiometric) point in the titration of 41 mL of 0.47 M (CH3)2NH(aq)(aq).  The Kb of dimethylamine is 5.4 x 10-4.