Ch.12 - SolutionsWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Determine the mass in grams of glucose (180.1 g/mol) that must be added to 63 g of water to make a 2.47 m solution.  Give your answer to 2 decimal places.A.  2.8x104 gB. 4.59 gC. 2.80 gD. 444 gE. 28.0

Problem

Determine the mass in grams of glucose (180.1 g/mol) that must be added to 63 g of water to make a 2.47 m solution.  Give your answer to 2 decimal places.

A.  2.8x104 g
B. 4.59 g
C. 2.80 g
D. 444 g
E. 28.02 g/mol

Solution

We’re being asked to determine the mass of glucose that must be added in 63 g of water to make a 2.47 m solution.


Recall that molality is the ratio of the moles of solute and the mass of solvent (in kilograms)


In other words:


Molality(m)=moles solutekg solvent


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