Use the concept of thermochemistry and stoichiometry to determine ΔH of the reaction of 25 g Na2O2 upon reaction with water
It can be seen that 2 moles of Na2O2 produces -126 kJ of heat.
Calculating for the ΔH of the reaction:
For the following reaction, what is ∆H° when 25.0 g of Na2O2(molar mass = 77.98 g mol−1) is reacted with water?
2 Na2O2(s) + 2 H2O(l) → 4 NaOH(s) + O2(g) ∆H° = −126 kJ
(A) -20.2 kJ
(B) 87.4 kJ
(C) -126 kJ
(D) 20.2 kJ
(E) -87.4 kJ