Problem: A coffee cup calorimeter is used to determine ∆H for the following neutralization reaction:KOH(aq) + HCl(aq) → H2O(l) + KCl(aq)When 100. mL of 0.500 M KOH was added to 100. mL of 0.500 M HCl, the temperature of the resulting 200. gram solution increased from 23.40°C to 26.80°C. If the specific heat of the solution is 4.184 J g−1 °C−1 and the small heat capacity of the coffee cup calorimeter is ignored, what is the enthalpy of the neutralization per mole of H2O produced?(A) 28.5 kJ (B) -56.9 kJ (C) 14.3 kJ (D) 56.9 kJ (E) -28.5 kJ

FREE Expert Solution

Use the concept of calorimetry to determine the heat of neutralization between KOH and HCl using the provided molarities, volume and temperature


For this problem, follow the steps:


Step 1. Calculate change in temperature

Step 2. Determine the amount of heat released


The neutralization reaction of KOH(aq) and HCl(aq) is


KOH(aq) + HCl(aq) → KCl(aq) + H2O(l)

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Problem Details

A coffee cup calorimeter is used to determine ∆H for the following neutralization reaction:

KOH(aq) + HCl(aq) → H2O(l) + KCl(aq)

When 100. mL of 0.500 M KOH was added to 100. mL of 0.500 M HCl, the temperature of the resulting 200. gram solution increased from 23.40°C to 26.80°C. If the specific heat of the solution is 4.184 J g−1 °C−1 and the small heat capacity of the coffee cup calorimeter is ignored, what is the enthalpy of the neutralization per mole of H2O produced?

(A) 28.5 kJ 

(B) -56.9 kJ 

(C) 14.3 kJ 

(D) 56.9 kJ 

(E) -28.5 kJ

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