Use the concept of calorimetry to determine the heat of neutralization between KOH and HCl using the provided molarities, volume and temperature
For this problem, follow the steps:
Step 1. Calculate change in temperature
Step 2. Determine the amount of heat released
The neutralization reaction of KOH(aq) and HCl(aq) is
KOH(aq) + HCl(aq) → KCl(aq) + H2O(l)
A coffee cup calorimeter is used to determine ∆H for the following neutralization reaction:
KOH(aq) + HCl(aq) → H2O(l) + KCl(aq)
When 100. mL of 0.500 M KOH was added to 100. mL of 0.500 M HCl, the temperature of the resulting 200. gram solution increased from 23.40°C to 26.80°C. If the specific heat of the solution is 4.184 J g−1 °C−1 and the small heat capacity of the coffee cup calorimeter is ignored, what is the enthalpy of the neutralization per mole of H2O produced?
(A) 28.5 kJ
(B) -56.9 kJ
(C) 14.3 kJ
(D) 56.9 kJ
(E) -28.5 kJ
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