Ch.4 - Chemical Quantities & Aqueous ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: What is the stoichiometric coefficient for Pd(s) when the following equation is balanced using the smallest set of whole-number coefficients?Pd(s) + Sb3+(aq) → Pd2+(aq) + Sb(s)(A) 1 (B) 2 (C) 3 (D) 4 (E) 5

Problem

What is the stoichiometric coefficient for Pd(s) when the following equation is balanced using the smallest set of whole-number coefficients?

Pd(s) + Sb3+(aq) → Pd2+(aq) + Sb(s)

(A) 1 

(B) 2 

(C) 3 

(D) 4 

(E) 5

Solution

Balance the redox reaction of Pd(s) + Sb3+(aq) → Pd2+(aq) + Sb(s) where we have to find the coefficient of Pd(s)

  • Recall that when balancing chemical equations, we have to make sure that the number of elements on both sides is equal with the lowest whole number coefficients.
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