Problem: Ethylene glycol, which consists of C, H, and O, can be used as an antifreeze in automobile engines. A 20.69 g of ethylene glycol sample contains 8.01 g of C and 2.02 g of H. The molar mass of ethylene glycol = 62.07 g mol-1.(a) Determine the empirical formula for ethylene glycol (show your work):(b) Determine the molecular formula for ethylene glycol:

FREE Expert Solution

We’re being asked to determine the empirical and molecular formula of Ethylene glycol composed of C, H, and O, given the mass of the sample and of C and H.

Ethylene glycol, which consists of C, H, and O, can be used as an antifreeze in automobile engines. A 20.69 g of ethylene glycol sample contains 8.01 g of C and 2.02 g of H. The molar mass of ethylene glycol = 62.07 g mol-1.

Recall that the empirical formula is the simplest whole-number ratio formula of a compound. 


For this problem, we need to do the following steps:

Step 1: Calculate the moles of C, H, and O in the compound.

Step 2: Determine the lowest whole number ratio of C, H, and O to get the empirical formula.

Step 3: Determine the empirical mass

Step 4: Determine the molecular formula.


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Problem Details

Ethylene glycol, which consists of C, H, and O, can be used as an antifreeze in automobile engines. A 20.69 g of ethylene glycol sample contains 8.01 g of C and 2.02 g of H. The molar mass of ethylene glycol = 62.07 g mol-1.

(a) Determine the empirical formula for ethylene glycol (show your work):

(b) Determine the molecular formula for ethylene glycol:

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