Problem: How much energy is needed to convert 70.6 grams of ice at 0.00°C to water at 75.0°C? specific heat (ice) = 2.10 J/g°Cspecific heat (water) = 4.18 J/g°Cheat of fusion = 333 J/gheat of vaporization = 2258 J/gA. 45.6 kJB. 2.53 kJC. 182 kJD. 22.1 kJE. 34.6 kJ
FREE Expert Solution
We’re being asked to calculate the amount of energy required to convert 70.6 g of ice at 0.00˚C to water at 75˚C.
There are three heats involved in this problem:
1. q1 which is the heat in melting 70.6 g ice at 0.0°C.
2. q2 which is the heat in raising the temperature of 70.6 g of water from 0.00˚C to 75˚C.
We need to solve for each heat individually then add them together to get the final answer.
Problem Details
How much energy is needed to convert 70.6 grams of ice at 0.00°C to water at 75.0°C?
specific heat (ice) = 2.10 J/g°C
specific heat (water) = 4.18 J/g°C
heat of fusion = 333 J/g
heat of vaporization = 2258 J/g
A. 45.6 kJ
B. 2.53 kJ
C. 182 kJ
D. 22.1 kJ
E. 34.6 kJ