Ch.14 - Chemical EquilibriumWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds
Problem

The reaction      2 NO2(g) ⇌ N2O4(g)
is exothermic. This means that:

A. Kc will not change if the temperature is increased

B. Kc will be negative

C. Kc will decrease as the temperature is increased

D. The forward reaction is more sensitive to temperature than the reverse reaction

E. None of the above

Solution

We’re being asked to identify the correct statement for the given reaction:


2 NO2(g)  N2O4(g)          Exothermic


According to Le Chatelier’s Principle, if a system (chemical reaction) is at equilibrium and we disturb it, then the system will readjust to maintain its equilibrium state.



Since the reaction is exothermic, this means that ΔH = (–), heat is given off as a product:

2 NO2(g)  N2O4(g) + heat


The Kc expression for this reaction is:


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