Ch.14 - Chemical EquilibriumWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: At a given temperature, the equilibrium constant (Kp) for the reaction PCl5(g) ↔ PCl3(g) + Cl2(g) is 0.395 {also Kp= Kc(0.0821 T)}. What is the total pressure of the equilibrium system in mmHg if there are 100 mmHg of both PCl3(g) and PCl5(g) at equilibrium?a. 400. mmHgb. 300. mmHgc. 595. mmHgd. 500. mmHge. 200. mmHg

Problem

At a given temperature, the equilibrium constant (Kp) for the reaction PCl5(g) ↔ PCl3(g) + Cl2(g) is 0.395 {also Kp= Kc(0.0821 T)}. What is the total pressure of the equilibrium system in mmHg if there are 100 mmHg of both PCl3(g) and PCl5(g) at equilibrium?

a. 400. mmHg

b. 300. mmHg

c. 595. mmHg

d. 500. mmHg

e. 200. mmHg

Solution

We’re being asked to determine the total pressure at equilibrium.


PCl5(g) ↔ PCl3(g) + Cl2(g) 


Recall that the equilibrium constant is the ratio of the products and reactants

We use Kp when dealing with pressure and Kc when dealing with concentration:


Kp=PproductsPreactants     Kc=[products][reactants]


Note that solid and liquid compounds are ignored in the equilibrium expression.


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