Ch.14 - Chemical EquilibriumWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Ammonium iodide can dissociate to produce HI and ammonia, NH4I(s) ⇌ NH3(g) + HI(g). At 300 °C, Kp = 0.42. If 250. g of ammonium iodide is placed into a 3.00 L flask and heated to 300 °C, what is the partial pressure of ammonia at equilibrium?a. 0.84 atm b. 0.21 atmc. 0.42 atmd. 0.65 atme. 0.18 atm

Problem

Ammonium iodide can dissociate to produce HI and ammonia, NH4I(s) ⇌ NH3(g) + HI(g). At 300 °C, Kp = 0.42. If 250. g of ammonium iodide is placed into a 3.00 L flask and heated to 300 °C, what is the partial pressure of ammonia at equilibrium?

a. 0.84 atm 

b. 0.21 atm

c. 0.42 atm

d. 0.65 atm

e. 0.18 atm


Solution

We’re being asked to determine the partial pressure of Ammonia when 250 g of NH4I is placed in a 3 L flasked heated up to 300°C


 NH4I(s)  NH3(g) + HI(g)


Recall that the equilibrium constant is the ratio of the products and reactants.  We use Kp when dealing with pressure and Kc when dealing with concentration:


Kp=PproductsPreactants     Kc=[products][reactants]


Note that solid and liquid compounds are ignored in the equilibrium expression.

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