Problem: Mustard gas, S(CH2CH2Cl)2 can be made at room temperature as shown:SCl2(g) + 2 C2H4(g) <=> S(CH2CH2Cl)2(g)In a particular experiment, 0.816 M of SCl2 and 0.288 M C2H4 were mixed. At equilibrium,{S(CH2CH2Cl)2(g)} was 0.187 M.Calculate the value of Kc for the reaction.Give your answer to 2 decimal places.

FREE Expert Solution

We are being asked to calculate the equilibrium constant, Kc for the given equilibrium reaction:

SCl2(g) + 2 C2H4(g) ↔ S(CH2CH2Cl)2(g)


When dealing with equilibrium and Kc:

Kc → equilibrium units are in molarity 
Kc is an equilibrium expression:

Kc=productsreactants

only aqueous and gaseous species are included in the equilibrium expression
▪ the coefficient of each compound in the reaction equation will be the exponent of the concentrations in the equilibrium expression


Given:    SCl2(g) + 2 C2H4(g) ↔ S(CH2CH2Cl)2(g)


87% (258 ratings)
View Complete Written Solution
Problem Details

Mustard gas, S(CH2CH2Cl)2 can be made at room temperature as shown:

SCl2(g) + 2 C2H4(g) <=> S(CH2CH2Cl)2(g)

In a particular experiment, 0.816 M of SCl2 and 0.288 M C2H4 were mixed. At equilibrium,

{S(CH2CH2Cl)2(g)} was 0.187 M.

Calculate the value of Kc for the reaction.

Give your answer to 2 decimal places.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the ICE Chart concept. You can view video lessons to learn ICE Chart. Or if you need more ICE Chart practice, you can also practice ICE Chart practice problems.