Problem: A 7.92 mass % aqueous solution of ethylene glycol (HOCH2CH2OH) has a density of 1.15 g/mL. Calculate the molarity of the solution. Give your answer to 2 decimal places.a. 0.36 mb. 0.42 mc. 1.92 md. 1.47 me. 1.21 m

FREE Expert Solution

We’re being asked to calculate the molarity (M) of a 7.92% (wt/wt) ethylene glycol (C2H6O2solution


Recall that molarity is the ratio of the moles of solute and the volume of solution (in liters). In other words:


molarity = moles of soluteL of solution



We’re given the mass percent of C2H6O2 in water, 7.92%. Recall that mass percent is given by:



% mass= mass of C2H6O2mass of solutionx100



This means in 100 g of solution, we have 7.92 g C2H6O2 


The steps we need to do for this solution are:

Step 1: Calculate the moles of C2H6O2 

Step 2: Calculate the volume of the solution (in L).

Step 3: Calculate the molarity of the solution.


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Problem Details

A 7.92 mass % aqueous solution of ethylene glycol (HOCH2CH2OH) has a density of 1.15 g/mL. Calculate the molarity of the solution. Give your answer to 2 decimal places.

a. 0.36 m

b. 0.42 m

c. 1.92 m

d. 1.47 m

e. 1.21 m

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