We’re being asked to calculate the molarity (M) of a 7.92% (wt/wt) ethylene glycol (C2H6O2) solution
Recall that molarity is the ratio of the moles of solute and the volume of solution (in liters). In other words:
We’re given the mass percent of C2H6O2 in water, 7.92%. Recall that mass percent is given by:
This means in 100 g of solution, we have 7.92 g C2H6O2 .
The steps we need to do for this solution are:
Step 1: Calculate the moles of C2H6O2
Step 2: Calculate the volume of the solution (in L).
Step 3: Calculate the molarity of the solution.
A 7.92 mass % aqueous solution of ethylene glycol (HOCH2CH2OH) has a density of 1.15 g/mL. Calculate the molarity of the solution. Give your answer to 2 decimal places.
a. 0.36 m
b. 0.42 m
c. 1.92 m
d. 1.47 m
e. 1.21 m
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Calculate Molarity concept. You can view video lessons to learn Calculate Molarity. Or if you need more Calculate Molarity practice, you can also practice Calculate Molarity practice problems.
What is the difficulty of this problem?
Our tutors rated the difficulty ofA 7.92 mass % aqueous solution of ethylene glycol (HOCH2CH2O...as medium difficulty.