We’re being asked to calculate the molarity (M) of a 7.92% (wt/wt) ethylene glycol (C2H6O2) solution
Recall that molarity is the ratio of the moles of solute and the volume of solution (in liters). In other words:
We’re given the mass percent of C2H6O2 in water, 7.92%. Recall that mass percent is given by:
This means in 100 g of solution, we have 7.92 g C2H6O2 .
The steps we need to do for this solution are:
Step 1: Calculate the moles of C2H6O2
Step 2: Calculate the volume of the solution (in L).
Step 3: Calculate the molarity of the solution.
A 7.92 mass % aqueous solution of ethylene glycol (HOCH2CH2OH) has a density of 1.15 g/mL. Calculate the molarity of the solution. Give your answer to 2 decimal places.
a. 0.36 m
b. 0.42 m
c. 1.92 m
d. 1.47 m
e. 1.21 m