Determine the molality of a solution prepared by dissolving 9.52 g of heptane (C_{7}H_{1}_{6}) (100.2 g/mol) in 87 g of benzene (C_{6}H_{6}). Give your answer to 2 decimal places.

a. 1.09 m

b. 1.21 m

c. 1.56 m

d. 2.61 m

e. 1.28 m

Establish the molality equation and determine the molality of a mixture of 9.52 g heptane (C_{7}H_{1}_{6}) and 87 g benzene (C_{6}H_{6})

Recall that molality can be calculated as:

$\overline{){\mathbf{molality}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}\frac{\mathbf{moles}\mathbf{}\mathbf{of}\mathbf{}\mathbf{solute}}{\mathbf{kg}\mathbf{}\mathbf{of}\mathbf{}\mathbf{solvent}}}$

In this case, we need to convert the mass of heptane to moles and mass of benzene to kg

Molality