Ch.4 - Chemical Quantities & Aqueous ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: What is the concentration of FeCl3 in a solution prepared by dissolving 30.0 g of FeCl3 (molar mass = 162.2 g/mol) in enough water to make 275 mL of solution? A) 6.73 × 10-4 M B) 1.49 × 103 M C) 0.673

Problem

What is the concentration of FeCl3 in a solution prepared by dissolving 30.0 g of FeCl3 (molar mass = 162.2 g/mol) in enough water to make 275 mL of solution? 

A) 6.73 × 10-4

B) 1.49 × 103

C) 0.673 M 

D) 1.49 M

Solution

Using the provided mass of FeCland volume of the solution we can find the molarity of FeCl3

Recall that molarity can be calculated as:

View the complete written solution...