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Use the concept of limiting reactant to determine the theoretical yield of CO2 when 4 moles of C8H8 and 4 moles of O2 reacts.
The given reaction is already balanced, all we need is the molar mass of CO2:
CO2 1 C × 12.01 g/mol C = 12.01 g/mol
2 O × 16 g/mol O = 32 g/mol
Sum = 44.01 g/mol
Give the percent yield when 28.16 g of CO2 (molar mass = 44.01 g/mol) are formed from the reaction of 4.000 moles of C8H18 with 4.000 moles of O2.
2 C8H18 + 25 O2 → 16 CO2 + 18 H2O
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