Problem: What is ΔHrxn at 25C?ΔHf ° (H+) = 0.0 kJ/mol;ΔHf ° (OH-) = -230.0 kJ/mol;ΔHf ° (H2O) = -285.8 kJ/mol)H+ (aq) + OH- (aq) → H2O (l)A. -55.8 J/mol B. 53.3 J/mol C. -55.8 kJ/mol D. -60.0 kJ/mol E. 55.8 kJ/mol

FREE Expert Solution

We are asked what is ΔHrxn at 25°C for :

H+ (aq) + OH- (aq) → H2O (l)

Recall that ΔH˚rxn can be calculated from the enthalpy of formation (ΔH˚f) of the reactants and products involved:

ΔH°rxn=ΔH°f, prod-ΔH°f, react

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Problem Details

What is ΔHrxn at 25C?

ΔHf ° (H+) = 0.0 kJ/mol;

ΔHf ° (OH-) = -230.0 kJ/mol;

ΔHf ° (H2O) = -285.8 kJ/mol)

H+ (aq) + OH- (aq) → H2O (l)

A. -55.8 J/mol 

B. 53.3 J/mol 

C. -55.8 kJ/mol 

D. -60.0 kJ/mol 

E. 55.8 kJ/mol

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