We’re being asked to determine the amount of heat released by shale.

We will use the heat released by the copper piece to calculate its initial temperature. Recall that heat can be calculated using the following equation:

$\overline{){\mathbf{q}}{\mathbf{=}}{\mathbf{mc}}{\mathbf{\u2206}}{\mathbf{T}}}$

q = heat, J

• **+q** → **absorbs **heat

• **–q** → **l****oses **heat

m = mass (g)

c = specific heat capacity = J/(g·°C)

ΔT = T_{f} – T_{i} = (°C)

A calorimeter has 1 kg of water (heat capacity of H_{2}O = 4.184 J/g°C) and its heat capacity is 0.10 kJ/°C when it’s empty. The calorimeter increases 5.0°C when 3.9 g of oil shale is burned. The amount of heat released per gram of oil shale is:

A. 3.25 kJ/g

B. 5.5 kJ/g

C. 6.8 kJ/g

D. 7.0 kJ/g

E. 3.33 kJ/g

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Constant-Volume Calorimetry concept. You can view video lessons to learn Constant-Volume Calorimetry. Or if you need more Constant-Volume Calorimetry practice, you can also practice Constant-Volume Calorimetry practice problems.