Problem: If 266 J are required to increase the temperature of 15 g of graphite by 25°C, what is graphite’s specific heat capacity?A. 0.71 J/g°C B. 0.85 J/g°C C. 0.5 J/g°C D. 0.33 J/g°C E. None of the above

FREE Expert Solution

We’re being asked to determine the specific heat capacity of graphite.


Recall that heat can be calculated using the following equation:

q=mcT

q = heat, J

+qabsorbs heat
–qloses heat

 m = mass (g)
 c = specific heat capacity = J/(g·°C)
 ΔT = Tf – Ti = (°C)


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Problem Details

If 266 J are required to increase the temperature of 15 g of graphite by 25°C, what is graphite’s specific heat capacity?

A. 0.71 J/g°C 

B. 0.85 J/g°C 

C. 0.5 J/g°C 

D. 0.33 J/g°C 

E. None of the above

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