We’re being asked to determine the specific heat capacity of graphite.
Recall that heat can be calculated using the following equation:
q = heat, J
• +q → absorbs heat
• –q → loses heat
m = mass (g)
c = specific heat capacity = J/(g·°C)
ΔT = Tf – Ti = (°C)
If 266 J are required to increase the temperature of 15 g of graphite by 25°C, what is graphite’s specific heat capacity?
A. 0.71 J/g°C
B. 0.85 J/g°C
C. 0.5 J/g°C
D. 0.33 J/g°C
E. None of the above
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