# Problem: If 266 J are required to increase the temperature of 15 g of graphite by 25°C, what is graphite’s specific heat capacity?A. 0.71 J/g°C B. 0.85 J/g°C C. 0.5 J/g°C D. 0.33 J/g°C E. None of the above

###### FREE Expert Solution

We’re being asked to determine the specific heat capacity of graphite.

Recall that heat can be calculated using the following equation:

$\overline{){\mathbf{q}}{\mathbf{=}}{\mathbf{mc}}{\mathbf{∆}}{\mathbf{T}}}$

q = heat, J

+qabsorbs heat
–qloses heat

m = mass (g)
c = specific heat capacity = J/(g·°C)
ΔT = Tf – Ti = (°C)

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###### Problem Details

If 266 J are required to increase the temperature of 15 g of graphite by 25°C, what is graphite’s specific heat capacity?

A. 0.71 J/g°C

B. 0.85 J/g°C

C. 0.5 J/g°C

D. 0.33 J/g°C

E. None of the above