We’re being asked to determine the specific heat capacity of graphite.

Recall that heat can be calculated using the following equation:

$\overline{){\mathbf{q}}{\mathbf{=}}{\mathbf{mc}}{\mathbf{\u2206}}{\mathbf{T}}}$

q = heat, J

• **+q** → **absorbs **heat

• **–q** → **l****oses **heat

m = mass (g)

c = specific heat capacity = J/(g·°C)

ΔT = T_{f} – T_{i} = (°C)

If 266 J are required to increase the temperature of 15 g of graphite by 25°C, what is graphite’s specific heat capacity?

A. 0.71 J/g°C

B. 0.85 J/g°C

C. 0.5 J/g°C

D. 0.33 J/g°C

E. None of the above

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