Ch.8 - Periodic Properties of the ElementsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Comparing the ionization energies of chlorine, selenium and sulfur,a. S  > Se and S = Cl.b. S  > Se and S > Cl.c. S  < Se and S < Cl.d. S  > Se and S < Cl.e. S < Se and S = Cl.

Problem

Comparing the ionization energies of chlorine, selenium and sulfur,

a. S  > Se and S = Cl.

b. S  > Se and S > Cl.

c. S  < Se and S < Cl.

d. S  > Se and S < Cl.

e. S < Se and S = Cl.

Solution

Establish the ionization energy trend and rank the given elements to increasing IE

Ionization energy is the energy required to remove an electron from a gaseous atom or ion.

The trend of the ionization energies of the elements can be observed in the periodic table:

increases going from left to right of a period

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