Calculate the energy per mole of photon released by a microwave with a wavelength of 300 mm

Recall that the ** energy of a photon (E)** is given by:

$\overline{){\mathbf{E}}{\mathbf{=}}{\mathbf{hv}}}\left(1\right)$

where:

**h** = Planck’s constant (6.63× 10^{–34} J • s)

**v** = frequency (in s^{–1})

Also, recall that the frequency (v) and wavelength (λ) are related:

$\overline{){\mathbf{\lambda}}{\mathbf{=}}\frac{\mathbf{c}}{\mathbf{v}}}\left(2\right)$

where:

**c** = speed of light (3.0 × 10^{8} m/s)

My microwave operates at a wavelength of 300.0 mm (note units). What is the energy of a __mole__ of photons generated by this microwave? The value of Planck’s constant, h = 6.63 × 10^{-34} J s.

a. 4.3 kJ

b. 4.3 × 10^{-5} kJ

c. 330 kJ

d. 3.3 × 10^{-4} kJ

e. 5.5 × 10^{-25} kJ

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