Problem: Given the following thermochemical data: ∆H°f (kJ)I. P4(s) + 6 Cl2(g) ⟶ 4 PCl3(g) –1225.6II. P4(s) + 5 O2(g) ⟶ P4O10(s) –2967.3III. PCl3(g) + Cl2(g) ⟶ PCl5(g) –84.2IV. PCl3(g) + 1/2 O2(g) ⟶ POCl3(g) –285.7Calculate the value of ∆H° for the following reaction:P4O10(s) + 6 PCl5(g) ⟶ 10 POCl3(g)A. –110.5 kJ B. –610.1 kJ C. –2682.2 kJ D. –4562.8 kJE. –7555.0 kJ
FREE Expert Solution
We’re being asked to determine the enthalpy change (ΔHrxn) for the chemical reaction:
P4O10(s) + 6 PCl5(g) ⟶ 10 POCl3(g)
We can use Hess’s Law to determine the enthalpy change of the overall reaction from the given reactions:
Problem Details
Given the following thermochemical data:
∆H°f (kJ)
I. P4(s) + 6 Cl2(g) ⟶ 4 PCl3(g) –1225.6
II. P4(s) + 5 O2(g) ⟶ P4O10(s) –2967.3
III. PCl3(g) + Cl2(g) ⟶ PCl5(g) –84.2
IV. PCl3(g) + 1/2 O2(g) ⟶ POCl3(g) –285.7
Calculate the value of ∆H° for the following reaction:
P4O10(s) + 6 PCl5(g) ⟶ 10 POCl3(g)
A. –110.5 kJ
B. –610.1 kJ
C. –2682.2 kJ
D. –4562.8 kJ
E. –7555.0 kJ
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