Subjects
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Internal Energy | 22 mins | 0 completed | Learn |
Calorimetry | 39 mins | 0 completed | Learn |
Thermochemical Equation | 6 mins | 0 completed | Learn Summary |
Hess's Law | 17 mins | 0 completed | Learn |
Enthalpy of Formation | 13 mins | 0 completed | Learn Summary |
End of Chapter 6 Problems | 52 mins | 0 completed | Learn |
Additional Practice |
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Units of Energy |
Additional Guides |
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Endothermic & Exothermic Reactions |
Enthalpy |
Given the following thermochemical data:
∆H°f (kJ)
I. P4(s) + 6 Cl2(g) ⟶ 4 PCl3(g) –1225.6
II. P4(s) + 5 O2(g) ⟶ P4O10(s) –2967.3
III. PCl3(g) + Cl2(g) ⟶ PCl5(g) –84.2
IV. PCl3(g) + 1/2 O2(g) ⟶ POCl3(g) –285.7
Calculate the value of ∆H° for the following reaction:
P4O10(s) + 6 PCl5(g) ⟶ 10 POCl3(g)
A. –110.5 kJ
B. –610.1 kJ
C. –2682.2 kJ
D. –4562.8 kJ
E. –7555.0 kJ
We’re being asked to determine the enthalpy change (ΔHrxn) for the chemical reaction:
P4O10(s) + 6 PCl5(g) ⟶ 10 POCl3(g)
We can use Hess’s Law to determine the enthalpy change of the overall reaction from the given reactions:
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