Problem: A 30.0 mL of pure water at 280. °C is mixed with 50.0 mL of pure water at 330. °C. What is the final temperature of the mixture (density of water = 1.00 g mL-1)?A. 405 °CB. 326 °CC. 320. °CD. 311 °CE. 290. °C

FREE Expert Solution

Use the concept of calorimetry where the colder water at 280°C absorbs the heat from the hotter water at 330°C

In this problem, we can just assume that water has a density of 1 g/mL which makes 30 mL and 50 mL pure water having a mass of 30 g and 50 g respectively

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Problem Details

A 30.0 mL of pure water at 280. °C is mixed with 50.0 mL of pure water at 330. °C. What is the final temperature of the mixture (density of water = 1.00 g mL-1)?

A. 405 °C

B. 326 °C

C. 320. °C

D. 311 °C

E. 290. °C

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