Problem: What is the concentration of nitrate ions in a solution made by dissolving 14.3 g of Fe(NO3)3 (molar mass = 241.88 g mol-1) in enough water to form 0.135 L of solution?A. 2.30 M B. 0.766 MC. 0.435 MD. 1.31 ME. 4.35 x 10-4 M

FREE Expert Solution

We’re being asked to calculate the molarity (M) of nitrate ions in a Fe(NO3)3 solution.


Recall that molarity is the ratio of the moles of solute and the volume of solution (in liters). In other words:


Molarity (M) = moles of soluteLiters of solution


We first need to determine the number of moles of Fe(NO3)3.


We’re given the mass and molar mass of Fe(NO3)3 so we calculate using the equation below. 


Molar Mass = massmol mol= massMolar Mass mol= 14.3  g  241.88 g/mol

mol = 0.059 mol Fe(NO3)3 


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Problem Details

What is the concentration of nitrate ions in a solution made by dissolving 14.3 g of Fe(NO3)3 (molar mass = 241.88 g mol-1) in enough water to form 0.135 L of solution?

A. 2.30 M 

B. 0.766 M

C. 0.435 M

D. 1.31 M

E. 4.35 x 10-4 M


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