We’re being asked to calculate the molarity (M) of nitrate ions in a Fe(NO3)3 solution.
Recall that molarity is the ratio of the moles of solute and the volume of solution (in liters). In other words:
We first need to determine the number of moles of Fe(NO3)3.
We’re given the mass and molar mass of Fe(NO3)3 so we calculate using the equation below.
mol = 0.059 mol Fe(NO3)3
What is the concentration of nitrate ions in a solution made by dissolving 14.3 g of Fe(NO3)3 (molar mass = 241.88 g mol-1) in enough water to form 0.135 L of solution?
A. 2.30 M
B. 0.766 M
C. 0.435 M
D. 1.31 M
E. 4.35 x 10-4 M
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