Problem: What is the spectator ion(s) in the reaction: Pb(NO3)2(aq) + NaCl(aq) → PbCl2 + NaNO3a. Na+, Cl-b. Na+, Cl-, NO3-c. Cl-, NO3-d. Na+, NO3-e. Na+

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FREE Expert Solution

We’re being asked to identify the spectator ions in the reaction Pb(NO3)2(aq) + NaCl(aq) → PbCl2 + NaNO3 

We’re going to determine the spectator ions using the following steps:

Step 1 Write the total or full ionic equation
Step 2. Identify the spectator ions

Solubility Rules:

Soluble Ionic Compounds:

 Group 1A ions (Li+, Na+, K+, etc.) and Ammonium ion (NH4+) are soluble
Nitrates (NO3-), Acetates (CH3COO- or C2H3O2-), and most Perchlorates (ClO4-) are soluble
Cl-, Br-, and I- are soluble except when paired with Ag+, Pb2+, Cu+, Hg22+
Sulfates (SO42-) are soluble except those of Ca2+, Sr2+, Ba2+, Ag+, and Pb2+

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Problem Details

What is the spectator ion(s) in the reaction: Pb(NO3)2(aq) + NaCl(aq) → PbCl2 + NaNO3

a. Na+, Cl-

b. Na+, Cl-, NO3-

c. Cl-, NO3-

d. Na+, NO3-

e. Na+