Problem: What is the spectator ion(s) in the reaction: Pb(NO3)2(aq) + NaCl(aq) → PbCl2 + NaNO3a. Na+, Cl-b. Na+, Cl-, NO3-c. Cl-, NO3-d. Na+, NO3-e. Na+

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We’re being asked to identify the spectator ions in the reaction Pb(NO3)2(aq) + NaCl(aq) → PbCl2 + NaNO3 

We’re going to determine the spectator ions using the following steps:

Step 1 Write the total or full ionic equation
Step 2. Identify the spectator ions

Solubility Rules:

Soluble Ionic Compounds:

 Group 1A ions (Li+, Na+, K+, etc.) and Ammonium ion (NH4+) are soluble
Nitrates (NO3-), Acetates (CH3COO- or C2H3O2-), and most Perchlorates (ClO4-) are soluble
Cl-, Br-, and I- are soluble except when paired with Ag+, Pb2+, Cu+, Hg22+
Sulfates (SO42-) are soluble except those of Ca2+, Sr2+, Ba2+, Ag+, and Pb2+

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Problem Details

What is the spectator ion(s) in the reaction: Pb(NO3)2(aq) + NaCl(aq) → PbCl2 + NaNO3

a. Na+, Cl-

b. Na+, Cl-, NO3-

c. Cl-, NO3-

d. Na+, NO3-

e. Na+

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Complete Ionic Equations concept. You can view video lessons to learn Complete Ionic Equations. Or if you need more Complete Ionic Equations practice, you can also practice Complete Ionic Equations practice problems.

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Based on our data, we think this problem is relevant for Professor Bass & Hamilton's class at UMBC.