We are being asked to find the volume of 0.45 M NaCl can be prepared by diluting 150 mL of 0.78 M NaCl.

When we are **adding water (or solvent) to a solution** to decrease its concentration, we are **diluting **the solution. When dealing with **dilution **we will use the following equation:

$\overline{){{\mathbf{M}}}_{{\mathbf{1}}}{{\mathbf{V}}}_{{\mathbf{1}}}{\mathbf{=}}{{\mathbf{M}}}_{{\mathbf{2}}}{{\mathbf{V}}}_{{\mathbf{2}}}}$

M_{1} = initial concentration

V_{1} = initial volume

M_{2} = final concentration

V_{2} = final volume

**Calculate the ****final volume of the 0.45 M NaCl solution.**

Your lab partner messes up and accidentally makes the needed solution of NaCl too concentrated, 150.0 mL of a 0.78 M solution, when you needed 150.0 mL of a 0.45 M solution. You sigh, and add water to dilute the solution. What is the final volume of your corrected 0.45 M NaCl solution?

A. 86.5 mL

B. 1,730 mL

C. 260. mL

D. 520. mL

E. 192 mL

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Dilution concept. If you need more Dilution practice, you can also practice Dilution practice problems.