Problem: What mass of potassium carbonate (molar mass = 138.21 mol-1) is needed to prepare 450. mL of an aqueous solution with a potassium concentration of 0.475 M?A. 29.5 gB. 1.33 x 104 gC. 13.3 gD. 14.8 gE. 6.65 g

FREE Expert Solution

We’re being asked to calculate the mass of potassium (K2CO3) carbonate needed to prepare 450. mL of an aqueous solution with a potassium concentration of 0.475 M.


Recall that molarity is the ratio of the moles of solute and the volume of solution (in liters). In other words:


Molarity (M) = moles of soluteLiters of solution


We first need to determine the number of moles of potassium (K+). 


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Problem Details

What mass of potassium carbonate (molar mass = 138.21 mol-1) is needed to prepare 450. mL of an aqueous solution with a potassium concentration of 0.475 M?

A. 29.5 g

B. 1.33 x 104 g

C. 13.3 g

D. 14.8 g

E. 6.65 g

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