Ch.4 - Chemical Quantities & Aqueous ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: If 308 mL of 0.148 M NaCl solution is added to 228 mL of a 0.369 M NH4NO3 solution, the concentration of ammonium ions in the resulting mixture will be:A. 0.625 M B. 0.218 MC. 0.369 M D. 0.157 ME. 0 M

Problem

If 308 mL of 0.148 M NaCl solution is added to 228 mL of a 0.369 M NH4NO3 solution, the concentration of ammonium ions in the resulting mixture will be:

A. 0.625 M 

B. 0.218 M

C. 0.369 M 

D. 0.157 M

E. 0 M

Solution

Calculate the NH4+ (ammonium ion) produced from 228 mL of 0.369 M NH4NOand 308 mL NaCl

Recall that molarity can be calculated as:

Molarity = moles of soluteL of solution


NH4NO3 dissociates in water as:

View the complete written solution...