Problem: If 308 mL of 0.148 M NaCl solution is added to 228 mL of a 0.369 M NH4NO3 solution, the concentration of ammonium ions in the resulting mixture will be:A. 0.625 M B. 0.218 MC. 0.369 M D. 0.157 ME. 0 M

FREE Expert Solution

Calculate the NH4+ (ammonium ion) produced from 228 mL of 0.369 M NH4NOand 308 mL NaCl

Recall that molarity can be calculated as:

Molarity = moles of soluteL of solution


NH4NO3 dissociates in water as:

93% (50 ratings)
View Complete Written Solution
Problem Details

If 308 mL of 0.148 M NaCl solution is added to 228 mL of a 0.369 M NH4NO3 solution, the concentration of ammonium ions in the resulting mixture will be:

A. 0.625 M 

B. 0.218 M

C. 0.369 M 

D. 0.157 M

E. 0 M

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Osmolarity concept. You can view video lessons to learn Osmolarity. Or if you need more Osmolarity practice, you can also practice Osmolarity practice problems.

What is the difficulty of this problem?

Our tutors rated the difficulty ofIf 308 mL of 0.148 M NaCl solution is added to 228 mL of a 0...as medium difficulty.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Taylor's class at UTD.