Ch.4 - Chemical Quantities & Aqueous ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Separate solutions of ammonium sulfide and barium bromide are added to the same flask. Which of the following most accurately describes the reaction?I. Barium sulfide precipitates out of solution.II. Barium ions remain as spectator ions.III. Ammonium bromide precipitates out of solution.IV. Ammonium ions remain as spectator ions.A. I and IVB. II and III C. I onlyD. II onlyE. There is no reaction; all species remain as spectator ions.

Problem

Separate solutions of ammonium sulfide and barium bromide are added to the same flask. Which of the following most accurately describes the reaction?

I. Barium sulfide precipitates out of solution.

II. Barium ions remain as spectator ions.

III. Ammonium bromide precipitates out of solution.

IV. Ammonium ions remain as spectator ions.

A. I and IV

B. II and III 

C. I only

D. II only

E. There is no reaction; all species remain as spectator ions.

Solution

Determine the reaction between ammonium sulfide and barium bromide and analyze if it will produce a precipitate or not

Ammonium sulfide is composed of ammonium (polyatomic cation → NH4+and sulfide (polyatomic anion → S2-). Molecular formula will appear as (NH4)2S. Recall that for ionic compounds, the charge of the ion goes to the subscript of the counterion

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