Ch.10 - Molecular Shapes & Valence Bond TheoryWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: For an atom of oxygen, what is the greatest number of hybridized orbitals it can have?A. 1 B. 3 C. 6 D. 4 E. 0

Problem

For an atom of oxygen, what is the greatest number of hybridized orbitals it can have?

A. 1 

B. 3 

C. 6 

D. 4 

E. 0

Solution

Determine the electron orbitals of the valence electrons of an Oxygen atom and figure out how many orbitals can form hybrids

Recall that for a neutral element, Atomic number = # of protons = # of electrons. 


The atomic number of O is 8 which means O has 8 electrons. The location of O in the periodic table is shown below:



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