Chemistry Practice Problems Calculate Oxidation Number Practice Problems Solution: In the following reaction, the oxidation state (nu...

Solution: In the following reaction, the oxidation state (number) of chlorine changes from:2 Cr(OH)4-(aq) + ClO-(aq) + 2 OH-(aq) → 2 CrO42-(aq) + 3 Cl-(aq) + 5 H2O(I)A. -1 to -2B. +3 to +6C. +4 to +8D. +1 to -1E. -4 to +3

Problem

In the following reaction, the oxidation state (number) of chlorine changes from:

2 Cr(OH)4-(aq) + ClO-(aq) + 2 OH-(aq) → 2 CrO42-(aq) + 3 Cl-(aq) + 5 H2O(I)

A. -1 to -2

B. +3 to +6

C. +4 to +8

D. +1 to -1

E. -4 to +3

Solution

Determine the oxidation state/number of Cl in ClO- in the reactant side and Cl- in the product side

The rules for oxidation states are as follows:


A. General Rules:

1. For an atom in its elemental form (Zn, Cl2, C(graphite), etc.)    O.S. = 0

2. For an ion (Li+, Al3+, etc.)                                                       O.S. = charge


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