We’re being asked to draw a Lewis structure for ClCN. We first need to determine the total number of valence electrons present in the molecule:
Group Valence Electrons
N 5A 1 × 5 e– = 5 e–
C 4A 1 × 4 e– = 4 e–
Cl 7A 1 × 7 e– = 7 e–
Total: 16 valence e–
Select the best Lewis structure for ClCN.
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