Solution: Ammonia, NH3, reacts with the hypochlorite ion, OCl - to produce hydrazine, N2H4.2NH3 + OCl – → N2H4 + Cl – + H2OWhat is the percent yield of hydrazine when 5.85 g of NH 3 reacts with excess hypochlor

Ammonia, NH₃, reacts with the hypochlorite ion, OCl ^- to produce hydrazine, N₂H₄.

2NH₃ + OCl ^– → N₂H₄ + Cl ^– + H₂O

What is the percent yield of hydrazine when 5.85 g of NH ₃ reacts with excess hypochlorite to produce 2.60 g of N₂H₄? Molar mass: NH₃ = 17.031 g/mol; N₂H₄= 32.046 g/mol

A. 47.3%

B. 23.6%

C. 11.8%

D. 8.25%