# Problem: Ammonia, NH3, reacts with the hypochlorite ion, OCl - to produce hydrazine, N2H4.2NH3 + OCl – → N2H4 + Cl – + H2OWhat is the percent yield of hydrazine when 5.85 g of NH 3 reacts with excess hypochlorite to produce 2.60 g of N2H4? Molar mass: NH3 = 17.031 g/mol; N2H4= 32.046 g/molA. 47.3%B. 23.6%C. 11.8%D. 8.25%

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Ammonia, NH3, reacts with the hypochlorite ion, OCl - to produce hydrazine, N2H4.

2NH3 + OCl → N2H4 + Cl + H2O

What is the percent yield of hydrazine when 5.85 g of NH 3 reacts with excess hypochlorite to produce 2.60 g of N2H4? Molar mass: NH= 17.031 g/mol; N2H4= 32.046 g/mol

A. 47.3%

B. 23.6%

C. 11.8%

D. 8.25%

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