🤓 Based on our data, we think this question is relevant for Professor Tate's class at CSUSB.

A 0.200 M K_{2}SO_{4} solution is produced by ____.

A) dilution of 250.0 mL of 1.00 M K_{2}SO_{4 }to 1.00 L

B) dissolving 43.6 g of K_{2}SO_{4 i}n water and diluting to a total volume of 250.0 mL

C) diluting 20.0 mL of 5.00 M K_{2}SO_{4 }solution to 500.0 mL

D) dissolving 20.2 g of K_{2}SO_{4} in water and diluting to 250.0 mL, then diluting 25.0 mL of this solution to a total volume of 500.0 mL

E) dilution of 1.00 mL of 250 M K_{2}SO_{4} to 1.00 L

We are asked which of the following options would yield **0.200 M K _{2}SO_{4} solution**

When we are **adding water (or solvent) to a solution** to decrease its concentration, we are **diluting **the solution.

When dealing with **dilution **we will use the following equation:

$\overline{){{\mathbf{M}}}_{{\mathbf{1}}}{{\mathbf{V}}}_{{\mathbf{1}}}{\mathbf{=}}{{\mathbf{M}}}_{{\mathbf{2}}}{{\mathbf{V}}}_{{\mathbf{2}}}}$

M_{1} = initial concentration

V_{1} = initial volume

M_{2} = final concentration

V_{2} = final volume

Dilution