🤓 Based on our data, we think this question is relevant for Professor Tate's class at CSUSB.
A 0.200 M K2SO4 solution is produced by ____.
A) dilution of 250.0 mL of 1.00 M K2SO4 to 1.00 L
B) dissolving 43.6 g of K2SO4 in water and diluting to a total volume of 250.0 mL
C) diluting 20.0 mL of 5.00 M K2SO4 solution to 500.0 mL
D) dissolving 20.2 g of K2SO4 in water and diluting to 250.0 mL, then diluting 25.0 mL of this solution to a total volume of 500.0 mL
E) dilution of 1.00 mL of 250 M K2SO4 to 1.00 L
We are asked which of the following options would yield 0.200 M K2SO4 solution
When we are adding water (or solvent) to a solution to decrease its concentration, we are diluting the solution.
When dealing with dilution we will use the following equation:
M1 = initial concentration
V1 = initial volume
M2 = final concentration
V2 = final volume