We are asked which of the following options would yield 0.200 M K2SO4 solution
When we are adding water (or solvent) to a solution to decrease its concentration, we are diluting the solution.
When dealing with dilution we will use the following equation:
M1 = initial concentration
V1 = initial volume
M2 = final concentration
V2 = final volume
A 0.200 M K2SO4 solution is produced by ____.
A) dilution of 250.0 mL of 1.00 M K2SO4 to 1.00 L
B) dissolving 43.6 g of K2SO4 in water and diluting to a total volume of 250.0 mL
C) diluting 20.0 mL of 5.00 M K2SO4 solution to 500.0 mL
D) dissolving 20.2 g of K2SO4 in water and diluting to 250.0 mL, then diluting 25.0 mL of this solution to a total volume of 500.0 mL
E) dilution of 1.00 mL of 250 M K2SO4 to 1.00 L
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Dilution concept. If you need more Dilution practice, you can also practice Dilution practice problems.
What professor is this problem relevant for?
Based on our data, we think this problem is relevant for Professor Dixon's class at UCF.