Ch.7 - Quantum MechanicsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds
Problem

What is the wavelength (in nm) of the light emitted by a bar code scanner that has a frequency
of 4.62 x 1014 s-1?

a. 6.49 x 10-16 nm
b. 6.49 x 10-7 nm
c. 649 nm
d. 1.39 x 1014 nm
e. 1.39 x 1023 nm

Solution

We are being asked to calculate the wavelength of the light emitted with a frequency equal to 4.62 x 1014 s-1.


Wavelength, frequency, and the speed of light are connected by the following equation:

c=λν

c = speed of light, m/s
λ = wavelength, in m
ν = frequency, Hz (Hertz)


We can rearrange the equation to isolate the wavelength (λ):

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