🤓 Based on our data, we think this question is relevant for Professor Lapeyrouse's class at SEMINOLESTATE.

We’re being asked to **calculate the de Broglie wavelength** of an **electron**.

Recall that the ** de Broglie wavelength (λ)** can be calculated using:

$\overline{){\mathbf{\lambda}}{\mathbf{}}{\mathbf{=}}\frac{\mathbf{}\mathbf{h}}{\mathbf{m}\mathbf{\nu}}}$

where:

**h** = Planck's constant (6.626 × 10^{–34} kg • m^{2}/s)

**m** = mass (in kg)

**v** = velocity (in m/s).

We’re given:

mass = 9.11 × 10^{-28} g velocity = 7.40 × 10^{6} m/s

The de Broglie wavelength of an electron with a velocity of 7.40 × 10^{6} m/s is ________ m. The mass of the electron is 9.11 × 10^{-28} g.

A) 1.02 × 10^{10 }

B) 9.83 × 10^{-14}

C) 1.02 × 10^{13 }

D) 9.83 × 10^{-17 }

E) 9.83 × 10^{-11}

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the De Broglie Wavelength concept. You can view video lessons to learn De Broglie Wavelength. Or if you need more De Broglie Wavelength practice, you can also practice De Broglie Wavelength practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Lapeyrouse's class at SEMINOLESTATE.