Ch.7 - Quantum MechanicsWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: The de Broglie wavelength of an electron with a velocity of 7.40 × 106 m/s is ________ m. The mass of the electron is 9.11 × 10-28 g. A) 1.02 × 1010 B) 9.83 × 10-14 C) 1.02 × 1013 D) 9.83 × 10-17 E) 9.83 × 10-11

Problem

The de Broglie wavelength of an electron with a velocity of 7.40 × 106 m/s is ________ m. The mass of the electron is 9.11 × 10-28 g. 

A) 1.02 × 1010 

B) 9.83 × 10-14 

C) 1.02 × 1013 

D) 9.83 × 10-17 

E) 9.83 × 10-11

Solution

We’re being asked to calculate the de Broglie wavelength of an electron


Recall that the de Broglie wavelength (λ) can be calculated using:



λ = hmν


where:

h = Planck's constant (6.626 × 10–34 kg • m2/s)

m = mass (in kg)

v = velocity (in m/s)


We’re given:

mass = 9.11 × 10-28 g           velocity = 7.40 × 106 m/s


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