We’re being asked to **calculate the de Broglie wavelength** of an **electron**.

Recall that the ** de Broglie wavelength (λ)** can be calculated using:

$\overline{){\mathbf{\lambda}}{\mathbf{}}{\mathbf{=}}\frac{\mathbf{}\mathbf{h}}{\mathbf{m}\mathbf{\nu}}}$

where:

**h** = Planck's constant (6.626 × 10^{–34} kg • m^{2}/s)

**m** = mass (in kg)

**v** = velocity (in m/s).

We’re given:

mass = 9.11 × 10^{-28} g velocity = 7.40 × 10^{6} m/s

The de Broglie wavelength of an electron with a velocity of 7.40 × 10^{6} m/s is ________ m. The mass of the electron is 9.11 × 10^{-28} g.

A) 1.02 × 10^{10 }

B) 9.83 × 10^{-14}

C) 1.02 × 10^{13 }

D) 9.83 × 10^{-17 }

E) 9.83 × 10^{-11}

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