We’re being asked to calculate the de Broglie wavelength of an electron.
Recall that the de Broglie wavelength (λ) can be calculated using:
h = Planck's constant (6.626 × 10–34 kg • m2/s)
m = mass (in kg)
v = velocity (in m/s).
mass = 9.11 × 10-28 g velocity = 7.40 × 106 m/s
The de Broglie wavelength of an electron with a velocity of 7.40 × 106 m/s is ________ m. The mass of the electron is 9.11 × 10-28 g.
A) 1.02 × 1010
B) 9.83 × 10-14
C) 1.02 × 1013
D) 9.83 × 10-17
E) 9.83 × 10-11
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