Ch.6 - Thermochemistry WorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: If a balloon is inflated from a volume of 100.0 mL to 1.85 L against an external pressure of 1.00 atm, how much work is done (in J)? Hint: 1 L·atm = 101.3 JA. +0.85B. -177C. -1.75D. +180E. -101

Problem

If a balloon is inflated from a volume of 100.0 mL to 1.85 L against an external pressure of 1.00 atm, how much work is done (in J)? 

Hint: 1 L·atm = 101.3 J

A. +0.85
B. -177
C. -1.75
D. +180
E. -101

Solution

Calculate the work done by using the formula of pressure-volume-work equation:

W = -PV

where ΔV is 100 mL to 1.85 L 

P is 1 atm

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